# Water molecule bent shape and electron configuration [closed]

The hydrogen atoms in a water molecule are negatively charged, so they should repulse each other completely due to the electromagnetic force, forcing the hydrogen atoms to be on opposite sides of the oxygen atom. However, this is not the case, as the H-O-H bond angle is $$104.5 ^\circ$$.

Why does the lone electron pairs repulse the hydrogen atoms to an angle of $$104.5 ^\circ$$ in $$\ce{H2O}$$ instead of $$180 ^\circ$$?

## closed as unclear what you're asking by Jannis Andreska, A.K., orthocresol♦, Jan, Ben NorrisMay 9 '16 at 20:26

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• Y'know, it gets a bit disappointing to see someone with more than 10 posts who still doesn't format their posts with Mathjax properly. – M.A.R. Sep 7 '15 at 23:21
• @PhyCS Not sure what you're talking about... linear water in excited state? – Mithoron Sep 7 '15 at 23:55
• Possible duplicate of Why is H₂O V shaped? – Mithoron May 9 '16 at 17:53