I need help with a basic concentration problem.
If I have a $\mathrm{2~M}$ solution, and want to make a $\mathrm{0.1~M}$ solution of $\mathrm{100~ml}$, how would I go about that?
My work:
$$M_1V_1 = M_2V_2$$
Where $M_1 = \text{initial concentration}$, $M_2 = \text{final concentration}$, $V_1 = \text{volume needed from initial}$, $V_2 = \text{volume needed from final}$
$\mathrm{2~M \times V_1 = 0.1~M \times 100~ml}$
$\mathrm{V_1 = \frac{0.1~M \times 100~ml}{2~M} = 5~ml}$??
Therefore I need $\mathrm{5~ml}$ of my $\mathrm{2~M}$ solution, increased to $\mathrm{100~ml}$ to make a $\mathrm{0.1~M}$ solution of$\mathrm{100~ml~}$??