# Routes of formation of esters with highest yield

Esters can be formed in two ways according to the syllabus I'm following:

(1) Mixing an alcohol with a carboxylic acid in the presence of sulfuric acid; and

(2) Mixing an alcohol with an acid chloride.

My question is:

Which method produces the highest yield of esters?

I think method (2) does because the $\ce{Cl-}$ will attach with the $\ce{-OH}$ in alcohol. However, I'm not exactly sure of the reason. Can someone explain it clearly with full details please?

• Please visit this page, this page and this ‎one on how to format your future posts better.‎ || Excuse my ignorance, but what's the difference between 02 and 2? – It's Over Aug 13 '15 at 6:01
• Hold up, how do you get an ester from just an alcohol and an acid chloride? Did you mean mixing alcohols with some other compound in the presence of acid chloride? – chipbuster Aug 13 '15 at 6:17
• There is a method to form esters by adding an acid chloride to an alcohol. I actually meant that. – lucy G Aug 13 '15 at 6:37