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Freezing a full bottle of water tends to shatter the glass bottle. What if you used something tougher than glass, like diamond? What would happen if you kept dropping the temperature, but restrained the liquid volume so it couldn't freeze and what sort of force would the liquid exert on the container's walls?

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  • $\begingroup$ You'll want to look into the coefficient of thermal expansion for water. If you integrate the function over the temperature range in question, you will get the volume change. From that (as well as mass of substance and volume of container assumed to be static), you can calculate force (or pressure, if desired). $\endgroup$ – Todd Minehardt Aug 11 '15 at 0:32
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    $\begingroup$ For the record, we can currently generate pressures of nearly 640 gigapascal (roughly 6 million atmospheres) in specialized diamond anvil cells. $\endgroup$ – chipbuster Aug 11 '15 at 1:06
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Good question. Let's assume the container is infinitely strong, non-deformable, and constant in volume. Let's also assume that cooling the water is an equilibrium process -- that way, we won't have any supercooling.

At equilibrium, the first tiny bit of ice that freezes will take up more volume than the water it froze from. This will raise the pressure on the rest of the water. Eventually the pressure may get so high that additional freezing of more water is not thermodynamically favored.

Of course, as the pressure is raised, even the solid ice compresses a bit, freeing up a bit more volume for the liquid water. According to this paper from 2004, ice is less compressible than water, so as a starting assumption, it may be approximately true to neglect the ice compression effect.

Figure 4 from that same paper gives the freezing point depression of water as a function of pressure:

enter image description here

To fully answer your question, in addition to that data, an equation that gives pressure as a function of ice volume would also be needed. If we make the assumption I was talking about above -- i.e. that ice is incompressible, then from the data point that water has a constant compressibility of 46.4 ppm per atm we can come up with a very simple version of that equation.

$\frac{\Delta V_{water}}{V_{water}}=46.4 \times 10^{-6} \times P$, where P is the pressure in atmospheres.

Before freezing of a fraction $X$ of the water:

$$V_{ice} = X V_{tot}$$ $$V_{water} = (1-X) V_{tot}$$

After freezing:

$$ V_{ice} = X V_{tot} 1.11 $$ $$ V_{water} = (1-X) V_{tot} - \Delta V_{ice} $$

Combining those equations, you can get

$$0.11 \frac{X}{k(1-X)}= P$$, where $k$ is the compressibility of water. If even 1% of the water in the container freezes (and all our assumptions are true), then the pressure will be 24 atmospheres! Freezing 10% of the water would mean a pressure of 260 atmospheres. Looking at the chart above, reaching this point would require a temperature of only 271 or 272 K, i.e. only -1 °C or -2°C. Freezing 45% of the water would reach a pressure of 2000 atm, already off the chart above -- but the temperature required to reach that point would only be 253K or -20 °C, the setting of the average home residential freezer! ((Of course, at these extreme pressures, (i) ice is actually compressible, and (ii) the compressibility of liquid water is not constant but also a function of pressure, so the calculations would get quite a bit more complicated.))

The lesson is that for even moderate degrees of cooling, you'd need a very, very strong container.

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    $\begingroup$ I would add that 2000 atm (~200 MPa) we start seeing other phases of water, such as ice III. Given its density (1.16 g/cm3), I would expect either to see compressed ice I or compressed ice I mixed with ice III. $\endgroup$ – Dietrich Epp Aug 11 '15 at 3:13
  • $\begingroup$ Wouldn't it be something like instant water freeze experiment? $\endgroup$ – PTwr Aug 11 '15 at 11:20
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    $\begingroup$ You probably would ultimately get to situation where you get only ice compressed to starting density of water. $\endgroup$ – Mithoron Aug 11 '15 at 13:51
  • $\begingroup$ If the container isn't infinitely strong, the container could simply burst. This is exactly why you shouldn't leave beer contained in glass too long in the freezer. $\endgroup$ – Mast Aug 11 '15 at 19:58
  • $\begingroup$ You might want to add a reference to the water phase diagram $\endgroup$ – Bobson Aug 11 '15 at 20:30
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If, at atmospheric pressure, ice is less dense than liquid water (it is) then we have to use pressure to keep it from expanding during the freezing process. The amount of pressure required depends on the compressibility of water and ice in a fairly complex way.

The glass bottle in your example breaks because the pressure exceeds the tensile strength of the bottle. The details of converting pressure to stress in a material is more mechanical engineering than chemistry, but I would refer you to Wikipedia's cylinder stress page if you care to actually work through the calculations. If you made your bottle out of some magical material with infinite strength, the pressure would just keep increasing.

The details of what happens are pretty neat. Water can actually form lots of different kinds of ice with different crystal structures. Check out Wikipedia's phase diagram for more info. If you follow the freezing curve on that line, you'll see that with enough pressure the freeze temperature drops to ~250K!

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