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What is the product of 1,1-diphenylethanol + Montmorillonite K10 Clay undergoing microwave radiation? What is the mechanism for it?

My effort:

1,1-diphenylethanol + Montmorillonite K10 Clay catalyst used in a microwave-assisted synthesis of pyrazoles from enaminones.

Used for:

  • Support for catalysts
  • Preparation of clay nanopaper composites of nacre-like structure

Catalyst for:

  • Conversion of triose sugars with alcohols to alkyl lactates
  • Deprotection of ketone dimethylhydrazones

Is my answer correct?

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    – M.A.R.
    Jul 12, 2015 at 8:03
  • $\begingroup$ Montorillonite K10 is a solid acid catalyst and microwave is a source of heat, so... $$\ce{Ph2C(OH)CH3 ->[\ce{H+}][\Delta]}?$$ $\endgroup$
    – Ben Norris
    Jul 12, 2015 at 10:34

1 Answer 1

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Is my answer correct?

No! Your "answer" is just a random collection of facts and does not address the question.

Actually, Ben Norris has already kindly provided all the necessary information in his comment:

  1. Montmorillonite K10 is a solid, acidic catalyst.
  2. Microwave irradiation means that you are applying heat to the reaction.

Formation of 1,1-diphenylethene from 1,1-diphenylethanol

Under the given conditions, 1,1-diphenylethanol (1) is protonated, eliminates water (which might be driven out since heat is applied) and yields 1,1-diphenylethene (2).

Given that you're still applying heat in the presence of an acidic catalyst, the reaction will not stop here.

Protonation of 2 again results in the known bisbenzylic cation, which will add to a second molecule of 1,1-diphenylethene in Markovnikov fashion.

Dimerisation of 1,1-diphenylethene

The resulting intermediate is will undergo an intramolecular Friedel-Crafts alkylation which furnishes the indane derivative 3.

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