# How many electrons can have the quantum number set n=5, l=3, ml=-1? [closed]

How many electrons can have the quantum number set $n=6,\ l=3,\ m_l=-1$?

Also, please explain why. I know that n describes the number of shells in an atom but what do n, l, and ml have to do with electrons?

## closed as off-topic by Loong♦, Jannis Andreska, M.A.R., ron, bonJul 4 '15 at 17:12

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• Unfortunately, as $n$, $l$ and $m_l$ are directly related to the electrons, even if we answer this question, your confusion might remain. Would you mind adding more info about your thoughts about the problem and the concepts in it? – M.A.R. Jul 4 '15 at 16:07
• possible duplicate of What do the quantum numbers actually signify? – M.A.R. Jul 4 '15 at 16:07

This post answers the question of the of what the other quantum numbers mean:

As for how many electrons can have $n=5,\ l=3,\ m_l=-1$...

The Pauli Exclusion Principle states that two identical fermions (an eletron is a type of fermion) cannot occupy the same quantum state.

In other words, two electrons (in the same atom) cannot have identical quantum numbers.

• For each $n$, the values of $l=0,1,2,...,n$
• For each $l$, the values of $m_l=-l,...,-1,0,+1,...,+l$

For each $m_l$ there are only two allowed values of $m_s$, namely $m_s = + \frac{1}{2}$ and $m_s = -\frac{1}{2}$. Thus, each set of $\{n,l,m_l\}$ can only describe two electrons. In your case, we have two electrons with $n=5,\ l=3,\ m_l=-1$:

• $\{n,l,m_l,m_s\}=\{5,3,-1,+\frac{1}{2}\}$
• $\{n,l,m_l,m_s\}=\{5,3,-1,-\frac{1}{2}\}$