I have the formula $\ce{Co(C2O4)*H2O}$ in a reaction that forms cobalt oxide $\ce{Co3O4}$ – My data here says that my oxalate hydrate weighed 0.3283 g and my product oxide weighed 0.1158 g which I have calculated as 0.1158 × (176.79 g cobalt / 240.79 g cobalt oxide) to equal 0.08502 g of cobalt in the original sample. 0.3283 g of reactant − 0.1158 product gives me 0.2125 g water removed divided by 18.016 g/mol to get 0.01179 mol $\ce{H2O}$ in the sample.
How do I use this data to determine the empirical formula? I am not sure how to determine the molar ratios from this point. Any help would be greatly appreciated as I’ve been at this all day.