Today I was told:
When 2-chlorobutane is reacted with 2-chloropropane in the presence of sodium and dry ether the following products are formed:
3,4-dimethylhexane, being most symmetric, is the major product.
I'm not satisfied with the reason provided. Can anyone please explain the fact in a better manner?
What I'm unable to understand is that both 3,4-dimethylhexane and 2,3-dimethylbutane and equally symmetric since both have a plane of symmetry, don't they? Then how are we using symmetry to compare the yield?