My new try: Given data
Energy given by reaction =1690 kJ
Initial temperature = 0 oC
Final temperature = 50 oC
C water = 4.18 Jmol-1 K-1
?Hfus ice = 6.01 kJ*mol-1
Calculate Mass of ice = ?
Ice melts at constant temperature of 0 degree C and changes the phase from solid to liquid .
Then liquid water absorbs the energy and changes from 0 degree C to 50 degree C
Change in temperature of the water is ?T = (50 oC - 0 oC )= 50 oC
Let’s set up the equation as follows to calculate the mass of ice
q= (m*?Hfus) + (m*Cwater * ?T)
where , q = energy , m = mass , ?T = (Tf-Ti)
convert given energy from unit kJ to Joules
(1690 kJ * 1000 J)/1kJ = 1690000 J
Convert ?H fus from kJmol-1 to Jg-1
6.01kJ*mol-1 (1000 J/1kJ) = 6010 Jmol-1
6010 Jmol-1 / 18.0148 gmol- = 333.6 J *g-1
Convert C water from J per mol to J per g
4.18 Jmol-1 oC /18.0148 g = 0.232 J*g-1 oC-1
Now lets put the values in the formula and calculate the mass of ice
q= (m*?Hfus) + (m*Cwater * ?T)
1690000 J = (m X 333.6 Jg-1) + (m X 0.232 Jg-1 *oC-1 * 50 oC )
1690000 J = m X 345.2 J*g-1
1690000 J /345.2 J*g-1 = m
4895.7 g = m
Please help me!!