What will the $\ce{^129Xe}$ NMR spectrum of $\ce{XeOF4}$ look like?
I know that its electron pair geometry is octahedral, and the molecular pair geometry is square pyramidal.
I believe that the lone pair on $\ce{Xe}$ will take the equatorial position (less sterically crowded), alongside the oxygen and 2 other equatorial fluorines in the same plane, to minimize electron pair repulsion.
So there will be 2 equatorial $\ce{F}$ and 2 axial $\ce{F}$. Therefore, am I right to say that the $\ce{^129Xe}$ NMR will be a triplet of triplets?