# Preparation of 6-bromo-1-hexanol

I am refluxing $\ce{HBr}$ with 1,6-hexanediol for 16 hours at $80\ ^\circ\mathrm{C}$ in toluene. How can I be sure that more than $90\,\%$ of the product is brominated only at one terminal? If the amount of double brominated product is in more than $10\,\%$ of the total yield, then the product mixture will be useless for me.

• Would having unreacted 1,6-hexanediol be acceptable? If so, use it in excess. – jerepierre May 21 '15 at 15:55
• @ringo the &deg; is not typeset well in math equations in mathjax, it's probably better to use ${}^\circ$. – Martin - マーチン May 22 '15 at 4:12
• jerepierre what I am concerned about is the by product 1,6-dibromohexane which I can't allow to be there. – Punarbasu Roy May 22 '15 at 4:33