# Lewis Structure on (CH3)2NO?

I've been taking an chemistry class online (for fun only) and one of the questions in the homework threw me a bit. Here's the wording:

"Draw the Lewis structure for a nitrogen atom attached to. two methyl groups ($\ce{CH3}$) and one oxygen atom."

OK, so I know that $\ce{NO}$ is a free radical due to the odd combined valence, i.e., the octet rule isn't satisfied. Will that carry over when the $\ce{NO}$ bonds with the two methyl groups?

Here's the sketch of what I did:

Lastly, what's the name of this compound? This is not part of the HW question; I'm just curious.

• Name of the compund: Dimethyl nitroxide
• Lewis structure:

• The properly way to determine the Lewis structure, based on this example, is:

1. Total valence electrons: $4\cdot2 + 5 + 6 + 1\cdot6 = 25$
2. Total electrons needed for octets/doublets: $8\cdot4+2\cdot6 = 44$
3. Total shared/bonding electrons: $44 - 25 = 19$ (In other words, there is only nine single bonds and one electron left.)
4. Total electrons in lone pairs: $\text{Step 1} - \text{Step 3} = 25 - 19 = 6$ (In other words, the are only 3 pairs of lone electrons.)