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A molecule that has hydrogen bonding usually follows these two premises.

1.) There is a hydrogen atom involved

2.) Hydrogen must be bonded to a highly electronegative element which are nitrogen ($\ce{N}$), fluorine ($\ce{F}$) and oxygen ($\ce{O}$).

Seeing that both oxygen and chlorine have a small difference in their electronegativity (oxygen being roughly 3.5 and chlorine being roughly 3.0), why does chlorine in a hydrogen chloride molecule ($\ce{HCl}$) have a dipole-dipole interaction, while the oxygen in a water molecule ($\ce{H2O}$) causes the water molecule to have a stronger form of dipole-dipole interaction called hydrogen bonding? I do not understand this since chlorine is just as electronegative as oxygen and nitrogen?

Edit: I should also added that nitrogen and chlorine have the same EN value (3.0)

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    $\begingroup$ Related. Short answer: $\ce{Cl}$ is too large. $\endgroup$ – Asker123 May 17 '15 at 17:13
  • $\begingroup$ @Asker123 Could you go a little more in depth? $\endgroup$ – Luis Averhoff May 17 '15 at 17:14
  • $\begingroup$ Also, check out the example from this answer. $\endgroup$ – andselisk Jan 6 '18 at 14:31
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Very, very related. Check it for a more in depth answer.

Well, first-of-all you need to understand that the $\ce{H}$ bonding isn't actually bonding. It is just a covalent attraction. Also since $\ce{Cl}$ is larger than $\ce{N}$, $\ce{F}$ and $\ce{O}$ it does not make a strong $\ce{H}$ bond. The size of the $\ce{Cl}$ makes the dipole-dipole attraction weaker. However $\ce{N}$, $\ce{F}$ and $\ce{O}$ are smaller and thus have an $\ce{H}$ bond.

Although in reality, compared to other covalently bonded structures, $\ce{HCl}$ has a very strong covalent bond.

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Despite its electronegativity, size of chlorine atom is large and hence, electron density of chlorine is not sufficient to form Hydrogen Bonding. Hence, HCl does not have hydrogen Bonding.

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protected by Community Jun 27 at 6:54

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