My teacher taught me the formulas 'nS' and 'nS+(n-1)d' to find the highest and lowest oxidation state of transition elements. He gave the example of $\ce{Mn}$ and showed that the numbers were +2 and +7. But I did not understand it. So can please you give me a good explanation.

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    $\begingroup$ Welcome to chemistry.se! Please have a look at the help center and take the tour. Could you explain, what the variables in your formula stand for, please. $\endgroup$ – Martin - マーチン May 9 '15 at 11:41
  • $\begingroup$ @Martin Although OP should confirm, the "n" stands for the principal quantum number as "s" and "d" refer to the s and d orbitals. $\endgroup$ – Binary Geek May 9 '15 at 12:21
  • $\begingroup$ Electron configuration [Ar] 3d5 4s2 - could you be more specific about your lack of understanding? ;) $\endgroup$ – Mithoron May 9 '15 at 12:51
  • $\begingroup$ Well … what about $\ce{Mn2(CO)10}$ and $\ce{[Mn(CO)5]-}$? $\endgroup$ – Jan Jun 9 '15 at 21:53

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