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If I know the amount of oxygen in such a solution, how can I know the required concentration of sodium sulfite to be used and react as oxygen scavenger?

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From the equation \[\ce{2SO3^{2-} + O2 -> 2SO4^{2-} } \] you could conclude that you need (at least) 2 moles of sodium sulfite $(\ce{Na2SO3})$ for each mole of oxygen in solution.

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