If one took equimolar solutions of $\ce{Li}$ and $\ce{K}$, which would have higher conductivity? Is it the same for molar conductivity?

Say, $\ce{LiCl}$ and $\ce{KCl}$, of a litre each. Also, as Molar Conductivity = Conductivity / Molarity, are molar conductivity and conductivity directly proportional? Why or why not?


1 Answer 1


Since Li is highly solvated due to its small size, it's mobility is reduced and hence conductivity decreased.

  • 1
    $\begingroup$ I'm fine with this answer, but it would really pay if you be a little more elaborate. It might give some people a comment-like feeling. $\endgroup$
    – M.A.R.
    Apr 19, 2015 at 12:45
  • $\begingroup$ Hmm, don't remember it now. :) I think I did click looks OK, but a better answer garners more votes, ya know. :) $\endgroup$
    – M.A.R.
    Apr 19, 2015 at 15:35
  • $\begingroup$ Oh well, just saying. I think only a sentence can't help the OP (and they might be too shy to ask in their own post as a comment) You can leave this as is, or you can add a canonical and a comprehensive answer so that everyone else will be benefited. Oooh man! Now that will be helping. :) $\endgroup$
    – M.A.R.
    Apr 19, 2015 at 16:24
  • $\begingroup$ @MARamezani :D I was earlier going to post Since Li has less mobility, it has less conductivity. I think it's enough and galdful that I added due to... $\endgroup$
    – RE60K
    Apr 19, 2015 at 16:26

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