3
$\begingroup$

If one took equimolar solutions of $\ce{Li}$ and $\ce{K}$, which would have higher conductivity? Is it the same for molar conductivity?

Say, $\ce{LiCl}$ and $\ce{KCl}$, of a litre each. Also, as Molar Conductivity = Conductivity / Molarity, are molar conductivity and conductivity directly proportional? Why or why not?

|improve this question
$\endgroup$
1
$\begingroup$

Since Li is highly solvated due to its small size, it's mobility is reduced and hence conductivity decreased.

|improve this answer
$\endgroup$
  • 1
    $\begingroup$ I'm fine with this answer, but it would really pay if you be a little more elaborate. It might give some people a comment-like feeling. $\endgroup$ – M.A.R. Apr 19 '15 at 12:45
  • $\begingroup$ Hmm, don't remember it now. :) I think I did click looks OK, but a better answer garners more votes, ya know. :) $\endgroup$ – M.A.R. Apr 19 '15 at 15:35
  • $\begingroup$ Oh well, just saying. I think only a sentence can't help the OP (and they might be too shy to ask in their own post as a comment) You can leave this as is, or you can add a canonical and a comprehensive answer so that everyone else will be benefited. Oooh man! Now that will be helping. :) $\endgroup$ – M.A.R. Apr 19 '15 at 16:24
  • $\begingroup$ @MARamezani :D I was earlier going to post Since Li has less mobility, it has less conductivity. I think it's enough and galdful that I added due to... $\endgroup$ – RE60K Apr 19 '15 at 16:26

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.