In $\ce{[MnCl_6]}^{2-}$, $\ce{Mn}$ has +4 oxidation state which gives it a $\ce{3d^3}$ $\ce{4s^0}$ configuration. But how is it having 4 unpaired electrons?

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    $\begingroup$ @DhrubaBanerjee You can also visit ‎this page and this one ‎for a better tutorial. $\endgroup$ – M.A.R. Apr 7 '15 at 17:13
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    $\begingroup$ are you sure it was 2- , I mean the charge can be 3- on the complex. $\endgroup$ – DSinghvi Apr 8 '15 at 9:20
  • $\begingroup$ The complex you are asking about has an odd number of electrons, there is no way it can have four unpaired electrons. With three unpaired electrons it is in a quartet state though. Can you refer us to the source of your doubts, maybe it is a typo in a textbook. $\endgroup$ – Martin - マーチン Apr 9 '15 at 4:06

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