# How can I deduce the structure of my compound from this NMR spectra?

I have no idea how to determine the substituents on the aromatic ring from this NMR spectra. There is (or ‘might be’) a triplet on my NMR around $7.59 - 7.65\,\mathrm{ppm}$ which has 4 hydrogens in the same environment. If so, there must be two ortho substituents on two aromatic rings but I think the 4 Hs won’t be in the same environment.

I assume the substance to be the one I added here

• Welcome to Chemistry.se! Are you sure that the compound you have drawn corresponds to the spectrum you have obtained? There are two singlets. At 3.86 it corresponds to the methoxy group. I see nothing in the molecule that might correspond to the 1.56 signal. (Maybe it is just water?) All the signals in your aromatic range have little shoulders (there are no values picked in this spectrum), but you should be able to calculate the coupling constants, with that information you might be able to correspond them to the protons in you compound. In principle, you should not see any triplet. – Martin - マーチン Mar 23 '15 at 6:29

Remember that triplets must have a $1\,:\,2\,:\,1$ ratio, or they aren’t triplets. With this information in hand, go back into the aromatic region and think what you could have gotten. I have dropped enough clues, I hope.