I'm completely stuck on this one - I was doing an experiment in a lab and now I cannot find the molarity of an ion in a solution. I've looked everywhere on the web but after 2 hours of searching I couldn't find anything. Maybe I am looking in the wrong direction.

I mixed three solutions: 1mL of $\ce{0.1M ~CuSO4}$, $\ce{0.28 M ~~NH3}$ and water. This solution turned into

$$\ce{Cu(H2O)4^{2+} + 4NH3 = Cu(NH3)4^{2+} + 4H2O}$$

This turned the solution from light blue to dark blue-ish purple. The final mL of the mixed solutions was 25 mL. Now I am supposed to calculate the molarity of the $\ce{Cu(NH3)4^{2+}}$ ion. I am pretty sure that I only have to calculate the molarity of $\ce{Cu^{2+}}$ but I am not entirely sure. If you guys could give me some help on this I would be very grateful.

  • $\begingroup$ you need to know more information like the volume of the 0.1M solution and the volume of the final mixed solution to calculate the molarity of Cu(NH3)4^(2+) $\endgroup$ – DavePhD Mar 6 '15 at 18:53
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  • $\begingroup$ I'm sorry! I did forget to add the volume - I will add it right now. $\endgroup$ – Mia Mar 7 '15 at 20:46
  • 1
    $\begingroup$ Is the 1 ml also for the ammonia solution? $\endgroup$ – Binary Geek Mar 10 '15 at 10:08

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