# Calculating concentration and volume in acid metal reactions [closed]

In the reaction: $$\ce{3 Zn + 2 H3PO4 -> Zn3(PO4)2 + 3H2}$$

I know the initial mass of $\ce{Zn}$ to be 13.08 g and the volume of phosphoric acid to be 0.5 $\mathrm{dm^3}$. How do I work out the final concentration of $\ce{Zn(PO4)2}$ and the volume of $\ce{H2}$ gas evolved?

Once I work out the moles of Zn, are the moles of $\ce{Zn(PO4)2}$ just $\ce{Zn}$ moles/3?

## closed as off-topic by ron, Klaus-Dieter Warzecha, jerepierre, Philipp, Jannis AndreskaMar 2 '15 at 18:04

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• Your conclusion on the molar ratio of zinc phosphate and zinc is right and you'll figure out the rest too! – Klaus-Dieter Warzecha Mar 2 '15 at 16:10