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What would happen if I kept two copper plates and one zinc plate in a solution of dilute sulfuric acid, and joined two copper plates with wires?

(The wires would connect to a single wire and be joined from that wire to the single zinc plate.)

What would be the voltage? Will there be something wrong?

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  • $\begingroup$ Welcome to chemistry.SE! If you had any questions about the policies of our community, you can ‎visit the help center or take a ‎‎tour of the website.‎ || You lost me! :) $\endgroup$ – M.A.R. Feb 14 '15 at 12:53
  • $\begingroup$ The two copper plates will be at the same voltage, they have the same potential. $\endgroup$ – Yomen Atassi Feb 14 '15 at 19:51
  • $\begingroup$ It would be like connecting the positive of a battery to a wire and the end of that wire to the positive and then connecting that wire to a single wire, kinda useless... $\endgroup$ – AlanZ2223 Feb 14 '15 at 21:00
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Neglecting any resistance in the connecting wires, this situation is no different than having one large copper plate. If everything is connected together, you can't measure any voltage because the fermi levels of all the metals will be equal (at equilibrium). This is essentially shorting the terminals of a battery and the zinc will start to dissolve in the electrolyte and hydrogen will be produced at the copper electrodes. You can measure a potential difference between the copper plates and the zinc plate, if they're not shorted, but it won't be any different with one copper plate or two for an open circuit.

If you're actually using the cell to do work, you may get more work out of the cell with more copper area, as the larger surface area will result in less solution resistance and better diffusion.

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