# Titration of bases against HCl

Suppose I take three bases in a solution, $\ce{NaOH}$, $\ce{Na2CO3}$ and $\ce{NaHCO3}$, and I titrate this solution with $\ce{HCl}$. Since the strengths of the bases are different, does it mean that $\ce{HCl}$ would first react with the strongest base completely and then start reacting with the next strongest base?

• I would think that it would react with all three of them at once (since all of those bases give off $\ce{OH-}$ which $\ce{HCl}$ can react with), but you would find the $\ce{NaOH}$ go away first since it dissociates more completely. – Sparkery Jan 26 '15 at 23:12