4
$\begingroup$

A stability model premised on Lewis acid-base covalent bonding can be proposed to rationalize the stability shown by sulfides such as CuS and Ag2S. For instance, although the oxide anion is a stronger Bronsted base than sulfide anion, sulfide anion can be (and usually is) a stronger Lewis base than oxide anion since S has a lower EN than O. Furthermore, recall that Lewis base strength depends on the Lewis acid with which the Lewis base interacts. For the sulfide anion, since sulfide anion possess empty valence 3d orbitals, Lewis acid-base interactions are often very strong if the Lewis acid is a low oxidation state metal ion with a fairly large number of valence d electrons. for such cases, sulfide-to-cation sigma coordinate covalent bond formation couples with pi-type coordinate covalent bond formation because metal ion d-electron density "drifts" back to empty valence 3d orbitals on sulfide anion. This results in covalent bond interactions that have substantial, strong multiple ond character and formation of a metal-sulfide lattice which is rather macromolecular in character. In sum, such as lattice must be very stable ...

1) Is the above excerpt describing pi-backbonding?

2) Is pi-backbonding more favorable for metals in a low rather than a high oxidation state because such metals still have substantial electron density that needs to be stabilized - and preferably stabilized by something more electronegative than a metal?

3) Metal d-orbitals overlap with p or d-orbitals of the non-metal. How does this work? I always see diagrams such as these:

enter image description here

Is the overlap between the metal d-orbital and non-metal p-orbital as poor as depicted? Are the d-orbitals really at a 45 degree angle relative to the p-orbital?

4) How well is the above excerpt written? I feel that two improvements could be made:

A) The passage seems to imply that Bronsted acidity and basicity do not depend on the corresponding base or acid. Wrong implication. HCl in HBr solvent won't be a strong acid.

B) Why electron density might just "drift" to the non-metal could be explained explicitly. I.e. electronegativity.

$\endgroup$
  • $\begingroup$ Silver oxide and silver sulfide have roughly similar energy of formation. Given higher energy of atomization per atom for $\ce{O2}$ molecule in comparison to $\ce{S8}$, this suggests stronger bonding in $\ce{Ag2O}$ rather than in $\ce{Ag2S}$. $\endgroup$ – permeakra Jan 20 '15 at 0:30
  • $\begingroup$ @permeakra my professor makes the argument that Ag2S is MUCH less soluble than Ag2O in water (Ksp of Ag2S is ~10^-51 while Ksp of Ag2O does not even approach that by a few trillion trillion). Does his argument hold water? I was just thinking that this only suggests that one is less polar than the other (like dissolves like). $\endgroup$ – Dissenter Jan 20 '15 at 0:33
  • $\begingroup$ How Ksp of Ag2O can be measured, if $\ce{O^{2-}}$ does not exist in water solutions? $\endgroup$ – permeakra Jan 20 '15 at 7:52
  • $\begingroup$ @permeakra Ksp of Ag2O is not necessarily defined as [Ag+]^2[O^2-] ... goldbook.iupac.org/S05742.html $\endgroup$ – Dissenter Jan 20 '15 at 15:29
5
$\begingroup$

1) Yes and no ... the d-d orbital overlap will almost certainly have pi-orbital character (angular node along bond axis), and it could reasonably be considered "backbonding" because the electron density is going in the canonically "unexpected" direction (i.e. away from positively charged metal center). On the other hand, chemists (particularly inorganic chemists) usually restrict the phrase "pi-backbonding" to refer to back donation from the d-orbitals of a neutral or ionic metal center into anti-bonding orbitals of a ligand, typically an olefin or a carbonyl ligand.

2) Yes .. that's essentially correct ... d-orbitals tend to be rather diffuse, and so can overlap with lobes of diffuse orbitals on ligands (or counter-ions, as with the metal sulfides). In traditional metal-ligand pi-backbonding, lobes the d-orbitals overlap with lobes of an unoccupied anti-bonding orbital of the ligand. In the example given above, they overlap with lobes of unoccupied d-orbitals on the sulfur. For a given system, unoccupied, or virtual, orbitals tend to be much more diffuse than occupied orbitals.

3) Those diagrams are just intended to capture the qualitative aspects of the bonding interaction, such as the symmetries of the orbitals involved. Remember, the orbitals are 3-dimensional shapes that describe the probability of finding an electron with a particular set of quantum numbers in a given region of space. Depictions like the one in your post are helping to visualize the orbital by assuming a fairly tight "tolerance" for the probability. For example, those images might depict the surfaces that enclose 75% of the total probability density. If you expand that to 90%, or even 99%, the lobes maintain the same basic shapes but get much larger, which might make the overlap seem more significant, but could also be confusing for other reasons.

4) I think it is quite well-written, but I suppose it would depend on the broader context in which it was being presented. I guess it is presented at an inappropriately high level for an introductory chemistry textbook, for example.

$\endgroup$
  • 1
    $\begingroup$ "I guess it is presented at an inappropriately high level for an introductory chemistry textbook." Curiously enough, this is an excerpt from a freshman chemistry text. I like it, however ;). Even if it only took me a year or so to actually understand what the text was trying to say! $\endgroup$ – Dissenter Jan 11 '15 at 9:59
  • $\begingroup$ Also doesn't the d in d orbital stand for diffuse? $\endgroup$ – Dissenter Jan 11 '15 at 23:55
  • 2
    $\begingroup$ Actually, yes .. it's part of an old convention for grouping of spectral lines .. "sharp", "principal", "diffuse" and "fundamental" .. as it became known that these grouping arose from atomic levels with different angular momentum quantum numbers, the numbers themselves took on those designations: $s$ for $l=0$, $p$ for $l=1$, $d$ for $l=2$ and so on ... but it's just coincidental that "diffuse" is also qualitatively descriptive for the nature of the d-orbitals in my answer to your question. $\endgroup$ – dtmoore1971 Jan 12 '15 at 0:47
  • $\begingroup$ one last question; what do you think this line means? "This results in covalent bond interactions that have substantial, strong multiple ond character and formation of a metal-sulfide lattice which is rather macromolecular in character." What does it mean by macromolecular in character? What's micromolecular? $\endgroup$ – Dissenter Jan 12 '15 at 5:28

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.