# Elimination of bromide and acetate under reducing conditions

Here is the reaction that I didn't find the mechanism of; maybe you can help:
The conditions is zinc dust, when the solvent is acetic acid at 110°C 1h. the reagents are Sodium acetate, 2,3,4,5-tetraacetoxy-1,6-bromohexane and the product is 3-4-diacetoxy-1,5-hexadiene. There is also some evolution of gas (I don't know what it is, $\ce{HBr}$ or $\ce{CO2}$).
What reaction can lead to this elimination when it seems that no proton is leaving the molecule (instead of bromide) and acetate is leaving?

• Welcome to chemistry.SE! You might not see it a bad idea if you take some of your time to take a tour or visit the help center for common questions about our community. I suggest you see this link and this link in order to learn how to make your posts better. – It's Over Dec 27 '14 at 13:53
• Pardon me? I edited your Q but it seems that there are little typos you got there. Did you really use Actinium Hydroxide as your solvent?! Even if you did so, formula shouldn't be AcOH; am I wrong? – It's Over Dec 27 '14 at 13:55
• i meant an acetic acid sorry – k.s Dec 27 '14 at 14:59