# Friedel-Crafts Alkylation Using Alkenes: Mechanism

What is the mechanism by which benzene, cyclohexene and $\ce{AlCl3}$ form cyclohexylbenzene?

I believe that cyclohexene will form a bond with Al with its double bond. However, how do we get rid of the $\ce{AlCl3}$ now attached to the previous cyclohexene after the benzene attaches to the module?

MECHANISM OF ALKYLATION: At first, electrophile methyl carbonium ion ($$\ce{CH3}$$) is formed from $$\ce{CH3Cl3}$$ and $$\ce{AlCl3}$$, which, at the second step, attracted by $$\pi$$-electron of the benzene ring to form sigma complex. At last step, the approach of nucleophile like, $$\ce{AlCl4-}$$, one proton is given out from sigma complex to form stable product toluene