# Disproportionation Reactions of the Halogens: Writing balanced net ionic equations for four reactions. See details

I first conducted the following reactions, each in separate test tubes:

1. $\ce{NaBr}$ + $\ce{H2SO4}$ + $\ce{NaBrO3}$
2. $\ce{KI}$ + $\ce{H2SO4}$ + $\ce{KIO3}$

...with water and dichloroethane added to each as well.

Then, I removed the aqueous layer from each test tube and added $\ce{NaOH}$ to the dichloroethane layer in each.

1. (#1) $\ce{NaOH}$ added to dichloroethane
2. (#2) $\ce{NaOH}$ added to dichloroethane

So far, I have the following equations written:

1. $\ce{NaBrO3 + 5NaBr + 3H2SO4 -> 3Na2SO4 + 3H2O + 3Br2}$
2. $\ce{KIO3 + 5KI + 3H2SO4 -> 3K2SO4 + 3H2O + 3I2}$
3. $\ce{3Br2 + 6OH^{-} -> 5Br^{-} + BrO3^{-} + 3H2O}$
4. $\ce{3I2 + 6OH -> 5I^{-} + IO3^{-} + 3H2O}$

Please check my work. If without error, I just need to convert these to equations to net ionic.

• A list of 3 compounds is not a reaction. Is sodium bromate a reactant or a product? You are not being remotely clear about what experiment you did. – DavePhD Dec 2 '14 at 20:08
• @DavePhD I corrected the question for clarity. In the experiment, I put a small quantity of sodium bromide in one test tube and a similar quantity of potassium iodide in the other test tube. I then added 1 mL of water, 3 drops of 9M sulfuric acid, and 2 mL of dichloroethane to each. I then added a small quantity of sodium bromate to the first test tube and a similar quantity of potassium iodate to the other. – JaxBragg Dec 2 '14 at 20:27
• So, you're just checking if these equations are balanced? – John Snow Dec 2 '14 at 22:21
• @JohnSnow The original question was much different – DavePhD Dec 3 '14 at 1:21
• @JaxBragg looks almost right now, just missing a minus sign in equation 4, and 6 H2SO4 going to 6 NaHSO4 or 6 KHSO4 is more realistic in equations 1 and 2. – DavePhD Dec 3 '14 at 1:27