# Disproportionation Reactions of the Halogens: Writing balanced net ionic equations for four reactions. See details

I first conducted the following reactions, each in separate test tubes:

1. $$\ce{NaBr}$$ + $$\ce{H2SO4}$$ + $$\ce{NaBrO3}$$
2. $$\ce{KI}$$ + $$\ce{H2SO4}$$ + $$\ce{KIO3}$$

...with water and dichloroethane added to each as well.

(In the experiment, I put a small quantity of sodium bromide in one test tube and a similar quantity of potassium iodide in the other test tube. I then added 1 mL of water, 3 drops of 9M sulfuric acid, and 2 mL of dichloroethane to each. I then added a small quantity of sodium bromate to the first test tube and a similar quantity of potassium iodate to the other.)

Then, I removed the aqueous layer from each test tube and added $$\ce{NaOH}$$ to the dichloroethane layer in each.

1. (#1) $$\ce{NaOH}$$ added to dichloroethane
2. (#2) $$\ce{NaOH}$$ added to dichloroethane

So far, I have the following equations written:

1. $$\ce{NaBrO3 + 5NaBr + 3H2SO4 -> 3Na2SO4 + 3H2O + 3Br2}$$
2. $$\ce{KIO3 + 5KI + 3H2SO4 -> 3K2SO4 + 3H2O + 3I2}$$
3. $$\ce{3Br2 + 6OH^{-} -> 5Br^{-} + BrO3^{-} + 3H2O}$$
4. $$\ce{3I2 + 6OH -> 5I^{-} + IO3^{-} + 3H2O}$$

Please check my work. If without error, I just need to convert these to equations to net ionic.