# How to efficiently reduce of ilmenite to pure titanium?

I am looking for a process in which reduces ilmenite to pure titanium with the highest yield possible. We are to use a process of our choice or one that we have created in conjunction with FactSage to calculate the yield of titanium.

the materials we have available are:

• Pure Metals
• $\ce{Al, Ca, Mg, Na, Si}$
• Pure Non-metals
• $\ce{Ar, C, Cl2, H2, N2, O2, S }$
• Molecules
• $\ce{CH4, CO, CO2, HCl, H2O, H2S, NH4}$

There are a few process that come to mind such as reduction using Magnesium, $\ce{H2SO4}$, high temperature $\ce{CO2}$, but any help on which would be the most efficient combined with the highest yield would be great.

• @Micheal it would be better, if you would use the mhchem package to format chemistry, rather than HTML. – Martin - マーチン Nov 17 '14 at 7:38
• Thermite Reduction is easiest. – Lighthart Nov 17 '14 at 20:01

Ilmenite mainly consists of $\ce{TiO2}$ and iron oxides. The idealized formula of ilmenite is approximately $\ce{FeTiO3}$.
The titanium ore can be converted to titanium tetrachloride according to $$\ce{TiO2 + 2Cl2 + 2C -> TiCl4 + 2CO}$$ or $$\ce{2FeTiO3 + 7Cl2 + 6C -> 2TiCl4 + 2FeCl3 + 6CO}$$ (If a large content of iron oxides causes problem, it can be partially removed first by partial reduction with carbon.)
Finally, titanium tetrachloride can be reduced to titanium sponge with magnesium (Kroll process): $$\ce{TiCl4 + 2Mg -> Ti + 2MgCl2}$$
The remaining $\ce{Mg}$ and $\ce{MgCl2}$ can be removed with hydrochloric acid.