In the context of automobile repair work, assume a metal surface has rust on it. Does it matter if all of the rust is removed before the metal surface is painted? If it does matter, then why?
It appears that at least some will claim you can do this, e.g. the company Krylon.
How I've tried to figure this out myself:
I'm assuming that the rust-covered surface area will affect how well the paint will stick to the surface. Maybe this alone can be a problem in terms of durability and sealing the metal from the atmosphere?
If it is governed by a more complex process, what process(es) should be read into further? However, I also assume that (as the aforementioned link suggests) that making the surface as smooth as possible with loose rust and debris removed will yield better results -- i.e. results that approximate that of having no rust at all there? Will it never be as good as simply having all rust removed? I know I'm asking in a way that is difficult to quantify, but "how good" will it get, compared to having all the rust removed?
After studying the Wikipedia article on rust I also imagine that from the dehydration equilibria we have that even a small area of rust can: $$\ce{Fe(OH)2 <=> FeO + H2O}$$
Even assuming the rust is properly sealed from the atmosphere it appears it can create new $\ce{H2O}$ under this protective layer.
But we need oxygen for the key reaction to occur: $$\ce{O2 + 4e^- + 2H2O -> 4OH^-}$$
From this how stuff works I have:
As the acid is formed and the iron dissolved, some of the water will begin to break down into its component pieces -- hydrogen and oxygen.
How exactly is the water broken down into hydrogen and oxygen? From a chemistry textbook (Masterton & Hurley) I have:
For example, water does not spontaneously decompose to the elements by the reverse of the reaction referred to above $$\ce{2H2O(l) -> 2H2(g) + O2(g)}$$ nonspontaneous.
But electrolysis can certainly create these elements. But can it happen in this environment? Sealed under a surface of paint? What does the chemistry look like?
From chemical formula I have that we can get hydroxide from: $$\ce{4e^- + 2H2O(l) + O2(g) -> 4OH^-(aq)}$$
However still, from where does new oxygen get introduced into the system, assuming the atmosphere is actually completely isolated from this internal system taking place under the surface of the paint?
Should it matter, assume the environment is approximately 1-atmosphere pressure and that the temperature varies between -10 to 40 degrees Celsius.