# Mechanism for reaction between aluminium and iodine [closed]

What should be a suitable mechanism for the reaction between aluminium and iodine, catalysed by water?

In my initial approaches, I had first thought of repeated attacks of the lone pairs of oxygen in water on aluminium, then formation of $\ce{Al(OH)3}$ by losing $\ce{H+}$, then $\ce{H+}$ attacking $\ce{I2}$, and formation of $\ce{HI}$, and finally formation of $\ce{AlI3}$.

But actually $\ce{Al2I6}$ is formed, so how can I accommodate its formation in that?

Is anything wrong in the above suggested mechanism? If the actual mechanism is something else, please write it in your answer.

A Lewis dot structure of the mechanism would be appreciated.

## closed as off-topic by Todd Minehardt, Mathew Mahindaratne, Jon Custer, Mithoron, Geoff HutchisonOct 7 at 0:05

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• There are a lot of problems in your proposed mechanism, which you would notice if you actually wrote the equations out. – DHMO Jan 24 '17 at 15:17
• The biggest problem is of course, my initially thought mechanism does not give me $\ce{Al2I6}$ , and that is why I asked this question. – Rohinb97 Jan 28 '17 at 12:43
• $\ce{Al2I6}$ is just the dimer of $\ce{AlI3}$; if you generate the latter in a reaction equation you can stop there (potentially add $\ce{2 AlI3 <=>> Al2I6}$ at the end) – Jan Oct 2 at 7:27
• How is this a homework question? Why is this put on hold even though I have literally explained my initial approach? – Rohinb97 Oct 9 at 14:00
• @Jan I don't see the reason this would just pop up in the end. Mechanisms usually incorporate the step of instability which leads up to dimerazation – Rohinb97 Oct 9 at 14:02