# How to calculate the volume of dry hydrogen in magnesium/ HCl reaction [duplicate]

I am not sure if the equivalents of $\ce{H2}$ in the equation $$\ce{Mg (s) + 2HCl (aq) -> MgCl2 (aq) + H2}$$
is that of dry or wet hydrogen.

If the $\ce{H2}$ refers to wet hydrogen in the equation, how should I find the volume of dry hydrogen given the pressure of wet and dry hydrogen and the volume of wet hydrogen?

• The water is a liquid. It exerts a vapor pressure. Some of the pressure in the gas is not due to hydrogen, it is due to water vapor so it is called wet hydrogen. Oct 19, 2014 at 16:58
• Not a duplicate, plus the linked question does not have an answer. Nov 27, 2017 at 12:28