What happens to 1,5-dimethyl-6,8-dioxabicyclo[3.2.1]octane when it is hydrolyzed under acidic conditions?
I know that under acidic conditions the first thing to likely happen is protonation. Does it matter which oxygen is protonated first?
Once that oxygen has been protonated it is going to want to return to neutrality.
Now we have our carbonyl restored (sort of). However, we still want to return to neutrality. Water can attack.
Then we deprotonated the attached water and regenerate the acid-catalyst and we have our original starting compound.
Is this the correct mechanism and is the product correct?