I've found out about something called resonance but I'm getting the impression that this indicates the kekule structure is possibly correct as it uses double bonds (I thought that the delocalised model was the only correct one).

I'm a little confused on this so could someone clarify?

  • $\begingroup$ There is very good video on Khan Academy you can watch it. This is kind of confusing topic, which to me was solved bu this video :) $\endgroup$
    – Freddy
    Oct 15, 2014 at 17:30

2 Answers 2


In benzene, all of the carbon-carbon bond lengths are equal. Therefore, the Kekule structure shown below is an incorrect representation of benzene.

enter image description here

It is incorrect because it suggests that there are two different types of carbon-carbon bonds in benzene, a carbon-carbon double bond and a carbon-carbon single bond. Typically, the bond length in a carbon-carbon double bond is around 135 pm, a carbon-carbon single bond is around 147 pm long, while the carbon-carbon bond length in benzene is roughly in between at 140 pm.

Benzene is often drawn as follows to indicate that all of the carbon-carbon bonds have the same length and the pi electron system is continuous and uniformly distributed.

enter image description here

Sometimes, when one is discussing the resonance properties of benzene, two Kekule structures are drawn with the double headed resonance arrow between them as shown below. This is meant to indicate that these two Kekule structures are resonance structures of benzene, and that taken together (e.g. in one Kekule structure a carbon-carbon bond is a single bond, in the other structure the same bond is a double bond; so "real" benzene is a simultaneous, superposition of these two structures where each carbon-carbon bond is in between a single and double bond), they represent the true electronic and physical structure of benzene.

enter image description here

  • $\begingroup$ So is drawing the resonance structure (with the double headed arrows) equivalent to the structure with circle in the middle (with the delocalised electrons)? So the resonance structure isnt implying that theres double and single bonds present that are constantly alternating to produce bonds which appear to be the same length? $\endgroup$
    – user58953
    Oct 15, 2014 at 15:57
  • 4
    $\begingroup$ You're exactly correct, the resonance structures with the double headed arrows are equivalent to the single structure with circle in the middle. The resonance structures are meant to imply that the bonds are 1) not alternating and 2) a simultaneous blend of single and double bonds. $\endgroup$
    – ron
    Oct 15, 2014 at 16:01

In defence of Kekulé structures

The real answer is, in my view, much more nuanced than ron's answer would have one believe. I sincerely think it is too simplistic to just say that it is "wrong".

To understand what I mean, we need to look at the concept of a resonance hybrid, which is a weighted average of several different resonance contributors. Molecules, of course, do not exist as individual resonance forms (not even fleetingly); they exist solely as the hybrid. We already understand that the most accurate depiction of benzene is one which comprises two major resonance contributors, 1a and 1b:

Resonance forms of benzene

One could argue that the only correct depiction of benzene is the resonance hybrid 1, where each pair of adjacent carbons is connected by 1.5 bonds, and indeed this position has already been argued. But benzene is not the only molecule in which resonance is crucial. Take an amide, for example: we know that the charge-separated resonance form is important to understanding (amongst others) the rigidity of the peptide bond, as well as its resistance towards hydrolysis.

Resonance forms of N,N-dimethylacetamide

Of course, here the C–O bond order is probably more than 1.5, and the C–N bond order is probably less than 1.5, but I don't have any other fancy ways of depicting non-integer bond orders, so we have to make do with this. According to the same logic as before, the only correct way of depicting the amide is the resonance hybrid 2, and using the individual resonance form 2a must be "wrong". However, it appears that the vast majority of organic chemists have no qualms about depicting amides in that form.

The same can be said of practically any other molecule, like butadiene, which is arguably even worse:

A selection of resonance forms of butadiene

Are we not being inconsistent, then, if we claim that the Kekulé structure of benzene – i.e. one of two resonance forms of benzene – is "wrong"?

Part of the answer to this paradox is that not all resonance structures are created equal. It is obvious that in benzene, the resonance forms 1a and 1b make an equal contribution to the resonance hybrid 1. Therefore, by choosing to solely depict benzene as 1a, we are effectively throwing away 50% of the information. On the other hand, the resonance form 2a is a larger contributor than 2b to the resonance hybrid; so, by choosing to solely depict the amide as 2a, we do not discard quite as much information.

However, it still leaves us with the uncomfortable question of where we should draw the line when it comes to the supposedly "wrong" practice of using resonance forms to represent molecules. Any threshold that we come up with, naturally, can only be completely arbitrary: you could draw up an arbitrary list of what is "permissible" and what is "wrong", but you would be doing it until the cows came home.

A much healthier way of resolving this contradiction, and one that the vast majority of chemists have already adopted, is to realise that our Lewis structure depictions are always going to be approximations to the truth. With this in mind, we can comfortably choose to use one resonance structure – the Kekulé structure, for example – and trust in the reader to understand that, unless stated otherwise, we are not referring specifically to this resonance form, but rather to the actual molecule, which exists as a resonance hybrid. And naturally, we should stick to the dominant resonance form as our default depiction of the molecule: hence for benzene we could use either 1a or 1b, but for the amide we should use 2a, not 2b.

Regarding benzene in particular, I guarantee you that the "circle in hexagon" depiction does not exist in organic chemistry beyond introductory textbooks which try to teach you that the Kekulé structure is "wrong". It is virtually impossible to find the "circle in hexagon" in a high-quality chemistry journal. [As always, there are exceptions: η6-benzene coordinated to metals is nearly always drawn with the circle, for example, but that is really a different story altogether.] Furthermore, using the circle makes it infinitely harder to explain a lot of aromatic chemistry: o/m/p-directing effects of substituents, or kinetic/thermodynamic sulfonation of naphthalene, to give two very basic examples.

The alternative to this is to be a purist: we must always draw dashed lines, and everything else is "wrong". If you want to be in that camp, so be it: congratulations, you are technically correct, but at what cost? Even IUPAC, the kings of being technically correct, don't care:

Curves represent delocalization, yet lots of structures have some delocalized elements. Although all such elements could be depicted with curves, there is little gained by doing so. On the contrary, the arbitrary use of curves can draw the viewer’s attention to insignificant portions of a structural diagram, and away from areas that are chemically more important such as an active site or a reactive group. Accordingly, curves should only be used when the delocalization is specifically being highlighted as an important feature of the structure.

When curves are not used, any alternating configuration of double bonds is acceptable within the further constraints discussed in GR-3.5.

Pure Appl. Chem. 2008, 80 (2), 277–410 (emphasis mine).


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