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Given complexation reactions for a specific Metal $X$ and Ligand $L$:

$$ XL_i + L \rightleftharpoons XL_{i+1}, k_i = \frac{XL_{i+1}}{XL_i \cdot L} $$

It's usual to draw a speciation diagram such those:

enter image description here enter image description here

If complexation constants are known, how such diagram can be drawn?

Disclaimer: I leave this question here while I intend to answer it myself because I think it can deserve the community. Feel free to comment or add your own answer. The only objective is sharing knowledge.

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1 Answer 1

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How?

For $n$ complexation reactions:

$$ XL_i + L \rightleftharpoons XL_{i+1}, k_i = \frac{XL_{i+1}}{XL_i \cdot L} $$

We can prodeed as follow:

  1. Write the sum of all complex species
  2. Highlight a specific species concentration you want to have the partition
  3. Rewrite concentration ratios as product of constants and ligand concentration
  4. Rework the expression to have a single fraction

For a 4-ligand complex, for the third specie from five it gives:

$$ \begin{align} C_t =& X + XL + XL_2 + XL_3 + XL_4 \\ C_t =& XL_2 \left[ \frac{X}{XL_2} + \frac{XL}{XL_2} + 1 + \frac{XL_3}{XL_2} + \frac{XL_4}{XL_2} \right] \\ C_t =& XL_2 \left[ \frac{1}{k_1k_2L^2} + \frac{1}{k_2L} + 1 + k_3L + k_3k_4L^2 \right] \\ \alpha_2 = \frac{XL_2}{C_t} =&\frac{k_1k_2L^2}{1 + k_1L + k_1k_2L^2 + k_1k_2k_3L^3 + k_1k_2k_3k_4L^4} \end{align} $$

This operation can be generalized for each specie, giving the following formula:

$$ \alpha_i = \frac{M_i(L)}{P(L)} = \frac{L^i\prod\limits_{j=0}^{i}k_i}{\sum\limits_{i=0}^n L^i\prod\limits_{j=0}^{i}k_i} $$

Where each ratio $\alpha_i \in [0,1]$ and $\sum\limits_{i=0}^n\alpha_i = 1$.

Notice all monomials $M_i(L) \geq 0$ because $L_i \geq 0$ and $k_i > 0$ which implies $P(L) \geq 1$. The Descarte's rule of sign also ensure $P(L)$ has no positive real root (they are only negative or complex). Ensuring each rational function $a_i$ well behaves over the concentration range.

The key point is the powerfulness of the technique that allows us to write the function wrt only constants $k_i$ and free ligand concentration $L$.

At this stage we can draw the first diagram:

enter image description here

If we desire the second, it sufficient to compute the total ligand concentration:

$$ L_t = \sum\limits_{i=0}^{n} i XL_i $$

Which allow us to draw the second diagram:

enter image description here

Both being useful to better visualize the complexation process with respect to experimental setup.

Additionally, determining specie partitions is a useful operation and can be rescaled simply by adjusting curves wrt $C_t$. It actually rationalize the complexation process.

Why?

I recently answered a question on Stack Overflow, and I wanted to share the knowledge with the Chemistry Stack community. If you are looking for code rendering such a diagrams, see the Python implementation.

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