I was reading the voltammetry section of Analytical Chemistry 2.1 (Harvey), and it says that for the reduction of $\ce{[Fe(CN)^{III}6]^3-}$ to $\ce{[Fe^{II}(CN)6]^4-}$, which has a standard reduction potential of +0.356 V, if a potential of +0.530 V is applied to a solution of 0.100 mM $\ce{[Fe(CN)^{III}6]^3-}$ and no $\ce{[Fe^{II}(CN)6]^4-}$, there will be no faradaic current or change of concentrations at the surface of the electrode.
Using the Nernst equation, I would expect the concentration of $\ce{[Fe^{II}(CN)6]^4-}$ at the electrode surface to be 0.00114 mM. Is the textbook rounding this down to zero, or is there truly no reduction well above the reduction potential?