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Given Molecule

I think that there is a chiral centers at $C_2$ and at $C_3$ (Numbering starting such that the carbon with hydroxy attached is number 2.

Then, for $C_2$:

  1. Priority would be: OH > $C_3$ > $C_1$ > H
  2. This makes it clockwise, so R

Then, for for $C_2$:

  1. Priority would be: Cl > $C_2$ > $C_4$ > H
  2. This makes it anticlock wise, so S

Therefore, the molecule becomes 2R, 3S 3-Chloro-2-pentanol.

Is this correct?

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    $\begingroup$ Clockwise/counterclockwise change their meaning depending on whether the H is facing towards you or away. $\endgroup$ Commented Oct 12, 2023 at 7:06
  • $\begingroup$ @IvanNeretin I know, however here I do not have any information about the H? Do I? $\endgroup$ Commented Oct 12, 2023 at 7:06
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    $\begingroup$ Now that looks correct to me. $\endgroup$ Commented Oct 12, 2023 at 7:53
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    $\begingroup$ @NaitikMundra A program like ChemDraw (sample page) can provide a check: draw the structure, mark them by the lasso, use the structure2name function (bottom row of the icons, the fourth counting from the right hand side). But: don't rely blindly on a computer program (which may include an [accidental] error of implementing the CIP rules, and nomenclature in general) -- continue your training to be able to apply the rules by yourself. $\endgroup$
    – Buttonwood
    Commented Oct 12, 2023 at 9:44
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    $\begingroup$ @NaitikMundra The site's resources actually compiled reference material about chemical nomenclature, too. $\endgroup$
    – Buttonwood
    Commented Oct 12, 2023 at 9:47

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