4
$\begingroup$

Both sodium borohydride and lithium aluminium hydride are common reducing agents in organic chemistry. Then can these reducing agents be applied in inorganic chemistry? I mean, for example, reducing acidified potassium dichromate, an inorganic compound.

$\endgroup$
1
  • $\begingroup$ NaBH4 and LiAlH4 are themselves both inorganic compounds, so yes, they can react with inorganic compounds. $\endgroup$ Commented Oct 5, 2023 at 6:31

1 Answer 1

7
$\begingroup$

In the case of sodium borohydride (which is more compatible with aqueous solutions), applications are known involving metal reduction. A few examples:

Precious metal recovery/recycle

Silver and platinum group metals are reducible from water-soluble salts using sodium borohydride. Initially the method was used for recovering silver from thiosulfate solutions used for photographic fixing; the application has now spread to recovery of "most precious metals". See Medding and Lander[1].

Wastewater treatment/Metal recovery

Sodium borohydride reduction can be used to remove certain heavy metals from wastewater, including copper. See Sithole et al. [2].

Ceramic nanomaterials

The reduction of cobalt chloride solution with sodium borohydride under controlled conditions yields $\ce{Co2B}$ powder with particle sizes 20-100 nm. See Jianming et al.[3].

References

  1. G.L. Medding, J.A. Lander, "Applications for sodium borohtdride in precious metal recovery and recycle", Editor(s): E.D. Zysk, Precious Metals 1981, Pergamon, 1982, Pages 3-10, ISBN 9780080253923, https://doi.org/10.1016/B978-0-08-025392-3.50007-7.

  2. N T Sithole, F Ntuli and T Mashifana (2018). "The Removal of Cu (II) from Aqueous Solution using Sodium Borohydride as a Reducing Agent". IOP Conf. Ser.: Earth Environ. Sci. 120 012022. DOI 10.1088/1755-1315/120/1/012022.

  3. Jianming Lu, D.B. Dreisinger, W.C. Cooper (1997). "Cobalt precipitation by reduction with sodium borohydride", Hydrometallurgy 45(3), 305-322, ISSN 0304-386X, https://doi.org/10.1016/S0304-386X(96)00086-2.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.