What kind of isomers does $\ce{[Co(NH3)5Cl]Cl2}$ exhibit?

I can rule out geometrical and optical due to there being $\ce{5 NH3}$ ligands which central metal atom cannot have different positions of $\ce{Cl}$ because there exists only one.

This does not show linkage isomerism because there is no bidentate or polydentate ligand for that , this does not show coordination or solvent isomerism because of No coordination second complex and no solvent in the chemical formula

Does this show ionization isomerism , as $\ce{NH3}$ could occupy the position of $\ce{Cl}$ in the front and we could have $\ce{[Co(NH3)3Cl3](NH3)2}$ but I am confronted on whether amine could occupy a counter ion's position where the counter ion exists to balance charge , yet there is no change of oxidation state of metal and then this transition could occur freely ?

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    – Poutnik
    Sep 30, 2023 at 7:33
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    – Poutnik
    Sep 30, 2023 at 7:42
  • $\begingroup$ But then the sum of charges does not fit. Possible are these: $\ce{[Co(NH3)6]Cl3}$, $\ce{[Co(NH3)5Cl]Cl2}$, $\ce{[Co(NH3)4Cl2]Cl}$, $\ce{[Co(NH3)3Cl3]}$. $\endgroup$
    – Poutnik
    Sep 30, 2023 at 9:11
  • $\begingroup$ can we have $\ce{[Co(NH3)3Cl3](NH3)2}$ $\endgroup$
    – Razz
    Sep 30, 2023 at 9:20
  • $\begingroup$ because Again for ionization isomerism , we get $\ce{2NH3}$as a product but , still not sure we can count this for ionization isomerism $\endgroup$
    – Razz
    Sep 30, 2023 at 9:21


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