On the back of an envelope: you start with $\pu{25 mL}$ of concentrated $\ce{HCl}$. Often seen among the suppliers, this is about $\pu{37.5 mass\%}$, or $\pu{12 mol/L}$ (reference), clearly corrosive. A dilution in $\pu{150 mL}$ of water yields a total volume of about $\pu{175 mL}$. With a dilution by a factor of 7 (you recall $n = c \cdot V$), the concentration now equates to $\pu{\approx 1.7 mol/L}$.
Your question does not detail out what salt you are going to isolate. An example could be light weight (organic) amines eventually isolated (thanks to differences of p$K_a$ values) as ammonium hydrochlorides. Here, the addition of the acid is just the necessary quantity to obtain the corresponding protonation, with practical no remaining corrosive acidity of $\ce{HCl}$ left. (Check with a droplet of the diluted solution on a stripe of pH paper.)
What scale we talk about?
$$n = c \cdot V$$
$$n = \pu{12 mol/L} \cdot \pu{25E-3 L} = \pu{0.3 mol}$$
For anilinium chloride obtained from aniline, for example, this corresponds to about $\pu{39 g}$ of product (with a reported density of $\pu{1.68 g/cm^3}$, less than $\pu{25 mL}$ occupied volume if it were a compact powder). So pick your heating plate from the shelf, a wide beaker, and a magnetic stirring bar to concentrate the diluted solution with gentle heating while stirring. This is a small setup to fit into a hood. Add the diluted solution in portions; when nearly dry, remove the magnetic stirring bar and stir with glass rod instead. As for OSHA, keep the sash down, protect your eyes, skin, clothing. (It doesn't leave a good impression about the chemistry and work ahead if you can't ask a TA / colleague [of your, or of an other group of the department], nor supervising PI for a safety check...)