The PIN (Preferred IUPAC Name) of this molecule


is (Z)-cycloocta-3-en-1,5-diyne, but at first I thought it was (Z)-cycloocta-1-en-3,7-diyne, following the rules of the Blue Book, P.31.1.3

Can someone help me to decipher the logic and the application of the naming rules to find the correct name of this type of structures?

  • 1
    $\begingroup$ The preferred IUPAC name is (3Z)-cyclooct-3-ene-1,5-diyne; note the three small differences. Subsection P-31.1.3 contains multiple rules. Which rule did you follow so that the numbering is changed? $\endgroup$
    – Loong
    Commented Feb 22, 2023 at 20:14
  • $\begingroup$ Is "PIN" an IUPAC abbreviation? If so, please don't use it. If not, just don't use it. ;) $\endgroup$
    – Karl
    Commented Feb 23, 2023 at 20:37

1 Answer 1


If by P.31.1.3, you meant P., then perhaps you misread it (emphasis mine):

In monocyclic homogeneous unsaturated compounds, one double or triple bond is always allocated the locant ‘1’. When alone, the locant ‘1’ is omitted in names.

Both of your given names are in accordance with this rule.

P- The presence of one or more double or triple bonds in an otherwise saturated parent hydride (...) is denoted by changing the ending ‘ane’ of the name of a saturated parent hydride to ‘ene’ or ‘yne’. Locants as low as possible are given to multiple bonds as a set, even though this may at times give ‘yne’ endings lower locants than ‘ene’ endings. If a choice remains, preference for low locants is given to the double bonds. In names, the ending ‘ene’ always precedes ‘yne’, with elision of the final letter ‘e’ in ‘ene’. (...)

Since the set of locants [1,3,5] is lower than [1,5,7], the name (Z)-cycloocta-3-en-1,5-diyne is preferred.


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