0
$\begingroup$

I'm thinking it will be linear with a negative charge on the middle bromine. Someone told me it is trigonal bipyramidal geometry with 3 lone pairs around the central bromine and the two other bromines above and below making it linear. Is this correct? Also is it just covalent bonding in the molecule?

$\endgroup$
1
  • 7
    $\begingroup$ Try looking up the structure of the triiodide ion. $\endgroup$
    – Dissenter
    Oct 6, 2014 at 23:21

1 Answer 1

1
$\begingroup$

In fact, tribromide ion has the generic formula $\ce{AX2E3}$ according to Lewis diagram. Where $\ce{A}$ is the central atom, $\ce{X}$ an atom bonded to $\ce{A}$ and $\ce{E}$ a lone pair on $\ce{A}$. Using Valence Shell Electron Pair Repulsion (VSEPR) theory, the geometry of this ion will be : enter image description here

So, the molecular shape is linear, while the electron pair geometry is trigonal bipyramid. And the bonds in the ion are covalent.

$\endgroup$
1
  • 3
    $\begingroup$ While VSEPR concludes on the correct geometry, the way it got there is just plain wrong. $\endgroup$ Oct 7, 2014 at 16:54

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.