It is possible to observe coupling between a hydroxyl proton and other protons. Why does the oxygen atom in ethers prevent any further coupling and act as a sort of barrier between spin systems? Or is coupling technically possible, but the resulting $^4\mathrm{J}$ coupling constant is just too small to be observed?
[Edit]: I initially asked this question because we learned in our spectroscopy lecture that proton couplings across R-O-R, R-N-R and R-S-R (with R ≠ H) aren't really possible. It's nice to see that this is just a rule of thumb and that some coupling can occur.
Could you tell me if my reasoning for the coupling in the examples below is correct or not: Fermi contact interactions are usually the most important mechanism for spin-spin coupling. The carbon atoms in the furane derivate are $\ce{sp^2}$ hybridized, so there should be additional σ-π-spin-polarization interactions. The carbonyl-carbon of the formate ester also has a lower s-character. The large $^5\mathrm{J}$ coupling in the trioxaadamantane derivate is the most surprising. In contrary to what I initially thought, the coupling mechanism seems to be different from the stereospecific sigma-bond contributions that are responsible for "W-coupling" (so maybe some through-space mechanism?).
Here is the original adamantane paper for anyone whos interested: https://doi.org/10.1021/ja00958a011
Quote from the paper: "The coupling systems in I and VII differ from these in that rotation of 180 and 120° about the central bond has taken place. If one mechanism is responsible for all the five-bond couplings cited, it must be independent of the geometry of the central bond."
So let me ask a slightly better question: Is there any difference between $^4\mathrm{J}_{\ce{HCCCH}}$ and $^4\mathrm{J}_{\ce{HCOCH}}$ coupling in acyclic, unstrained, $\ce{sp^3}$ hybridized molecules (i.e. do things like lone pairs play a role in spin-spin coupling and if so, why)?