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Given the following phase diagram for a binary mixture of $\ce{MoO3}$ and $\ce{Bi2O3}$:

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I am asked to determine whether from $\ce{Bi2O3}$ and $\ce{Bi6Mo2O15}$, can $\ce{Bi10Mo3O24}$ and $\ce{Bi14MoO24}$ be synthesized? And why?

I have checked the given answer and it says the 1st reaction is possible, and the second one isn't. Any ideas?

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    $\begingroup$ Convenient reference for text/formula formatting: Notation basics / Formatting of math/chem expressions / upright vs italic // For more: Math SE MathJax tutorial. // Not to be applied in CH SE titles. $\endgroup$
    – Poutnik
    Commented Nov 20, 2022 at 13:49
  • $\begingroup$ E.g. write $\ce{H2SO4}$ or $\ce{a A <=> p P}$ or $\pu{6.022E23 mol-1}$ to get $\ce{H2SO4}$ or $\ce{a A <=> p P}$ or $\pu{6.022E23 mol-1}$ (all eventually with double dollars in the display mode like $$\ce{H2SO4}$$. $\endgroup$
    – Poutnik
    Commented Nov 20, 2022 at 13:57
  • $\begingroup$ Given an appropriate mixture of the two, either can be made with some effort, since those compositions fall between your two given phases. We’re there other restrictions? $\endgroup$
    – Jon Custer
    Commented Nov 20, 2022 at 15:33

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