0
$\begingroup$

When a gas is compressed using external pressure (piston-cylinder assembly) we say work is done on the gas and it increases the internal energy of the gas.

Where does this work mainly go ? Does it increase the Kinetic energy of the molecules (work energy theorem), does it increase the potential energy of the molecules since we are doing work against internal conservative intermolecular forces of the gas, or it goes to something else ?

Also can temperature of a gas be increased by work only ?

$\endgroup$

2 Answers 2

4
$\begingroup$

What happens depends upon whether the change is done isothermally or adiabatically.

Suppose the gas is ideal then the internal energy $U$ depends only on temperature and is independent of the volume or pressure (by definition) and therefore for an isothermal expansion/compression $dU=0$ and so by the first law $dq=-dw$ where the work is $dw=-pdV$ and for an ideal gas $p=RT/V$. As the internal energy and temperature is unchanged, so is the kinetic energy. In a real gas at low pressure intermolecular interactions can be ignored and this behaves as if an ideal gas. (If this is not the case then $p$ would have to be given by, say, the van-der Waal equation which greatly complicated any calculation, but some work will be needed to compensate for the intermolecular forces).

In the adiabatic case no heat leaves or enters the system (i.e. no heat exchanged with surroundings) and therefore and expansion or compression is done at the expense of the internal energy and the temperature will change. The change in internal energy is given from the first law as $dU=dw$. On compression the temperature rises. If the gas is one of atoms then there is only kinetic energy which increases. In a gas of molecules, kinetic energy also increases but additionally rotational /vibrational energy levels can be populated according to the Boltzmann distribution.

The original experiments by James Joule (1843, in a brewery in Manchester, England) showed that mechanical work results in an increase in temperature; "Wherever mechanical force is expended, an exact equivalent of heat is always obtained."

$\endgroup$
3
$\begingroup$

Where does this work mainly go?

It speeds up the gas particles as the collide with a wall moving toward them. A quantitative description (for a monoatomic or diatomic gas) is given here:

https://en.wikipedia.org/wiki/Adiabatic_process#Example_of_adiabatic_compression

The temperature of the gas increases, so the pressure goes up more than the compression ratio when the process is adiabatic.

[..] does it increase the potential energy of the molecules since we are doing work against internal conservative intermolecular forces of the gas, or it goes to something else ?

The particles are far away from each other, so intermolecular forces can be neglected (in an ideal gas model, there aren't any except for the interactions with the wall).

Also can temperature of a gas be increased by work only?

Yes, imagine a giant stir bar bumping into the gas (shaft work - this is more commonly invoked for liquids, see this historical account, but should work for gases as well).

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.