For example for this reaction:
Step 1: $\ce{CO(g) + 2H2(g) -> CH3OH(l)}$
Step 2: $\ce{CH3OH(l) -> CH4(g) + 0.5 O2(g)}$
for step 1, when computing the standard heat of formation
𐤃H = 𐤃H($\ce{CH3OH}$) - 𐤃H($\ce{CO}$)
I don't include hydrogen gas because its "element is in its standard state so 𐤃H=0".
What does it mean by standard state and how would I know ?