# Which proton is more acidic in this compound?

I'm having trouble determining which of these protons is more acidic. I was thinking the solution had something to do with the double bond in the aromatic ring, but I'm still not sure. If anyone can help, I'd greatly appreciate it.

• This should be a $C_2$ symmetric molecule, making the $\ce{N-H}$ protons equivalent. Generally, they are more acidic than $\ce{C-H}$ protons. – Martin - マーチン Sep 28 '14 at 7:03