For a lab exercise to calibrate volumetric glassware I was given the follow equation to correct weighings for the density of air:
$$m_\mathrm{c} = m_\mathrm{s}\,\frac{1 - \rho_\mathrm{a}/\rho_\mathrm{c}}{1 - \rho_\mathrm{a}/\rho_\mathrm{s}},$$
where:
- $m_\mathrm{c}$ is the corrected mass of the sample;
- $m_\mathrm{s}$ is the measured mass of the sample tared for the container;
- $\rho_\mathrm{a}$ is the density of air;
- $\rho_\mathrm{c}$ is the density of weights used to calibrate the balance, assumed brass;
- $\rho_\mathrm{s}$ is the density of the sample.
Does $\rho_\mathrm{s}$ include the container for the sample? How is $\rho_\mathrm{s}$ determined without knowing $m_\mathrm{c}$?
If the tared container does not affect the calculation, $\rho_\mathrm{s}$ for water is straightforward. What about other material?