0
$\begingroup$

A generic reagent A is considered. The behavior equations of a CSTR reactor is the following:

$$ \tau = c_\mathrm{A,0} \intop_0^{X_\mathrm{A,final}} \dfrac{1}{-r_\mathrm{A}} dX_\mathrm{A} $$

where $\tau$ where it is the filling time, understood as the time required to make a fluid flow rate react whose volume is equal to the reactor volume

$$ \tau = \dfrac{V_\mathrm{reactor}}{\dot{V_\mathrm{A}}} $$

$c_\mathrm{A,0}$ is the initial concentration of A, and $X_\mathrm{A}$ and it is the conversion of A that we want to obtain

From Octave Levenspiel, Chemical Engineering Reaction, John Wiley & Sons, Third Edition, page 103, you can see how the graph $-\dfrac{1}{r_\mathrm{A}} = f(X_\mathrm{A})$ has the shape of a crescent curve

enter image description here

I tried to reproduce this graph, using the formula

$$ -\dfrac{1}{r_\mathrm{A}} = \dfrac{\tau}{c_\mathrm{A,0} X_\mathrm{A}} $$

and what I get is a decreasing curve

enter image description here

My question is: to be able to reproduce the graphic in the text, which formula should I use?

$\endgroup$
1
  • 2
    $\begingroup$ The equation seems to show that $X_A/r_A$ is constant in time where $r_A=dC/dt$ which depends on time as does $X_A$, but this is not included in your graph. The book's graph apparently shows what happens generally when these time dependences are added to $r$ and $X$. You should check this as I'm not an expert in chem. eng. reactors. $\endgroup$
    – porphyrin
    Commented Aug 7, 2022 at 7:25

1 Answer 1

1
$\begingroup$

From http://home.ku.edu.tr/~okeskin/ChBI502/chbi502-Chapter_2.pdf

An irreversible reaction is considered.

$$\mathrm{A} \xrightarrow{k} \text{Products} $$

To find a relationship between $r$ and $X$, we start from the kinetic law

$$-r_\mathrm{A} = k\ c^n_\mathrm{A}$$

where $n$ is the order reaction. The conversion is given by the formula

$$ X_\mathrm{A} = \dfrac{c_\mathrm{A,0} - c_\mathrm{A}}{c_\mathrm{A,0}} $$

With a few simple algebraic steps, we get

$$ c_\mathrm{A} = c_\mathrm{A,0} (1 - X_\mathrm{A}) $$

Substituting in the kinetic law, we obtain

$$-r_\mathrm{A} = k\ c_\mathrm{A,0}^n (1 - X_\mathrm{A})^n$$

Multiplying the first and second members by $-1$, the desired equation is finally obtained

$$\dfrac{1}{-r_\mathrm{A}} = \dfrac{1}{k\ c_\mathrm{A,0}^n} \dfrac{1}{(1 - X_\mathrm{A})^n}$$

enter image description here

This curve has been plotted for $n = 1$, but analogous curves can be obtained for $n \neq 1$. The only difference is the curve slope, which is obvious since as $n$ changes, the rate dependence on the concentration changes (and therefore from $X_\mathrm{A}$)

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.