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How would be crystal field stabilization energy for the complex [Co(NH3)5Cl]²-? I guess that due to the presence of negative ligand Cl- 3 sets of d orbitals can be present with a dz²or dx²-y²orbital of a slightly little different energy.

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    $\begingroup$ Do $\ce{Cl}$ electrons interact with $\ce{e_g}$ or $\ce{t_{2g}}$ set of orbitals? $\endgroup$
    – ananta
    Jul 14, 2022 at 13:42
  • $\begingroup$ I do want to know too $\endgroup$
    – Sudhagar
    Jul 14, 2022 at 13:54

1 Answer 1

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When more than one type of ligands are present with some being SFL and others being WFL then, the final effect of those ligands dominate which are greater in number. So, in the given compound, ammonia is more than chlorine so effect of SFL dominates and you get inner orbital complex

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  • $\begingroup$ I wonder .. how this answer is connected to the question. $\endgroup$
    – Sudhagar
    Jul 14, 2022 at 19:22
  • $\begingroup$ Then what do you want to know, please clarify $\endgroup$
    – Ritil
    Jul 14, 2022 at 20:23
  • $\begingroup$ How the d orbitals are split - their energy level diagram under the influence of both the ligands! $\endgroup$
    – Sudhagar
    Jul 15, 2022 at 5:27

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