I'd call c. 6- (3 aminocyclohexyl- methylamino) cyclohexa-2,4-dien-1-one and d. 1r, 2s- 2 (2-formyl- 4-methoxycarbonyl-but-3-en-1yl) cyclobutanecarboxylic acidenter image description here

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    $\begingroup$ How do you see two amino groups in c? What you call a "4-methoxycarbonyl-but-3-en-1yl" substituent actually is 5-methoxy-5-oxopent-3-en-1-yl. $\endgroup$
    – Loong
    Jun 12 at 12:34
  • $\begingroup$ You're right. In c it's 6- (3 hydroxycyclohexyl- methylamino) cyclohexa-2,4-dien-1-one. Thank you $\endgroup$
    – Tony
    Jun 12 at 13:09
  • $\begingroup$ Are you sure you correctly labeled the second molecule's stereocenters? $\endgroup$ Jun 14 at 3:27


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