# What kind of rearrangement happens between 2,2,5-trimethylcyclopentanol and concentrated sulfuric acid?

Question:

My attempt:

After getting the carbocation after protonation, in order to form a more stable alkene, it rearranged the methyl group on the adjacent carbon so as to get the alkene in the option (b). I am confused that whether it should be "1,2 hydride shift" or should it be "1,2 methyl shift" because the migratory aptitude of $$\ce{H-}$$ group is more than $$\ce{CH3-}$$ but here if carbocation formation is the RDS (considering E1) should we not rearrange it to a more stable species?

• try considering the fact that 'b' is more substituted as compared to 'a' Jun 12 at 10:32
• Have a look into this chemistry.stackexchange.com/q/161776/115228 Jun 12 at 13:37
• Thank you so much, I did get the answer and the logic behind it 😀 Jun 12 at 15:54
• If you have satisfied with any answer try upvoting it. It gives encouragement for the users :-) Jun 12 at 16:13